Apple˚✧ (ia-study)’s Comments (group member since Sep 23, 2024)

Apple˚✧ (ia-study)’s comments from the Math Help!! group.

Soha wrote: "Yess"

oh ive a love-hate relationship with it

Soha wrote: "ikrr it SUCKS T_T"

is it that proving stuff......?

✝️Reagan wrote: "I understand none of that. Ig I haven’t learned it yet. I’m scared now🫣🫣"

its okayy its identities stuff 😭

✝️Reagan wrote: "I’m in ninth grade too😅. What does ^ mean?"

its for power since we cant type(?) it

So (a+b)^3 = a^3 + 3ab(a+b) + b^3
-> (a+b+c)^3 = (a+b)^3 + 3(a+b)(c)(a+b+c) +c^3
-> = a^3 + 3ab(a+b) +b^3 + 3(a+b)(c)(a+b+c) + c^3
[taking a+b as one unit and c as one]

LHS = ( a + b + c )^ 3 – a^ 3 – b^ 3 – c^ 3
Solving LHS:
( a + b + c )^3 – a^3 – b^3 – c^3 = [a^3 + 3ab(a+b) +b^3 + 3(a+b)(c)(a+b+c) + c^3] – a^3 – b^3 – c^3
= 3ab(a+b) + 3(a+b)(c)(a+b+c)
= 3(a+b) [ab + c(a+b+c)]
= 3(a+b) [ab + ac + bc +c^2]
= 3(a+b) [a(b+c) + c(b+c)]
= 3(a+b)(b+c)(a+c) = RHS

Soha wrote: "can someone pleasee help...tom is math exam lol
prove ( a + b + c )^ 3 – a^ 3 – b^ 3 – c^ 3 = 3 ( a + b ) ( b + c ) ( c + a )"

w8 i can try