School discussion

amie ☆ wrote: "am i allowed to do this? if not delete it!

how do i write the polynomial as a product of linear factors for
f(x) = x^2 + 6x + 2 ?"

you have to find what two number multiple to 2, and add to 6 (assuming the constant in front of the x^2 is 1). In this case, you cannot do that, so you will have a 'remainder' at the end of the process.

I normally set this up as a 2x2 table, x^2 top left, 2 bottom right. on the outside of the table, I would write the 'factors'. the x's on the top and left of the x^2 to show that those multiplied together equal x^2. then i'd find the two numbers that add to 6, but multiply to the smallest possible number, closest to 2. this would be 6 and 1.

(x+6)(x+1) would be your linear factors, with a remainder of -4, to get to 2. so your answer would be (x+6)(x+1) - 4

was that helpful?


[this is how I'm taught to do these equations]

Its fine if you make topics!

amie ☆ wrote: "kaylyn wrote: "amie ☆ wrote: "am i allowed to do this? if not delete it!

how do i write the polynomial as a product of linear factors for
f(x) = x^2 + 6x + 2 ?"

you have to find what two number ..."

🤗ofcc