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Moka/Annabeth's Math Help Thread
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May 26, 2021 10:10AM
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((Could you just put it as Moka’s?))
Well...I ran into a problem that’s...weird.
‘Assume points A, B, C are on the same line. If AB=8 and BC=3, then what is the length of AC?’
oh I know something like that
My teacher said this one was optional, just thought I would try it.
I do though but I need to write it down first
is there a picture?
How about this one?
‘How many ordered integer tuples (x,y,z) satisfy all the following inequalities?
2015 <= x < 2025
2015 <= x+y+z < 2025
2015 <= x+2y+4z < 2025’
‘How many ordered integer tuples (x,y,z) satisfy all the following inequalities?
2015 <= x < 2025
2015 <= x+y+z < 2025
2015 <= x+2y+4z < 2025’
Astra - Queen of the Stars wrote: "is there a picture?"
Astra I don’t think you’re supposed to chat in this thread. This is just for me and Henry.
Astra I don’t think you’re supposed to chat in this thread. This is just for me and Henry.
Moka wrote: "Astra - Queen of the Stars wrote: "is there a picture?"Astra I don’t think you’re supposed to chat in this thread. This is just for me and Henry."
oh sorry I didn't know
But those were just extra ones
Heres the some of the real “stuff” on my paper:
1. Multiply and reduce to lowest form (if possible) :
(i) 2/5 × 5/4
(ii) 1/3 × 15/8
(iii) 4/5 × 12/7
(iv) 15/16 × 10/12
1. Multiply and reduce to lowest form (if possible) :
(i) 2/5 × 5/4
(ii) 1/3 × 15/8
(iii) 4/5 × 12/7
(iv) 15/16 × 10/12
Well...I’m just bad at math then because I don’t know what to do. Can you help me?
Ok one sec I’m doing what you said...
Ok I’m done! Thank you so much! I have more tho ;-;
(So this is not review but it’s a bunch of stuff so there’re not all the same)
Find:
(i) 3/5 of a dollar
(ii) 3/4 of a year
(iii) 2/3 of a day
(iv) 5/8 of a kilogram
(v) 2/3 of an hour
(vi) 7/25 of a litre
Find:
(i) 3/5 of a dollar
(ii) 3/4 of a year
(iii) 2/3 of a day
(iv) 5/8 of a kilogram
(v) 2/3 of an hour
(vi) 7/25 of a litre
I got number vi and iv on my own. Thank you for the rest though!
Multiply the fractions:
(i) 2/9 by 4/5
(ii) 3/5 by 12
(iii) 2¹/₃ by 2/5
(iv) 5³/₄ by 2³/₇
This is the last part of my math!
(i) 2/9 by 4/5
(ii) 3/5 by 12
(iii) 2¹/₃ by 2/5
(iv) 5³/₄ by 2³/₇
This is the last part of my math!
Moka wrote: "((Could you just put it as Moka’s?))"
((No, cuz you hcange your name too many times.))
((No, cuz you hcange your name too many times.))
Astra - Queen of the Stars wrote: "Moka wrote: "Astra - Queen of the Stars wrote: "is there a picture?"
Astra I don’t think you’re supposed to chat in this thread. This is just for me and Henry."
oh sorry I didn't know"
No, it's fine. Astra, if you can help Moka, then you can!!
Astra I don’t think you’re supposed to chat in this thread. This is just for me and Henry."
oh sorry I didn't know"
No, it's fine. Astra, if you can help Moka, then you can!!
If you're just chatting, then no.
Henry wrote: "ok so when it says by it means multiply so you can essentially do the same thing as you did earlier when you posted
\1. Multiply and reduce to lowest form (if possible) :
(i) 2/5 × 5/4
(ii) 1/3 ×..."
Ohhhhhhh ok! Thank you for your help! That was the last part of my math :>
\1. Multiply and reduce to lowest form (if possible) :
(i) 2/5 × 5/4
(ii) 1/3 ×..."
Ohhhhhhh ok! Thank you for your help! That was the last part of my math :>
Elizabeth L. wrote: "Astra - Queen of the Stars wrote: "Moka wrote: "Astra - Queen of the Stars wrote: "is there a picture?"
Astra I don’t think you’re supposed to chat in this thread. This is just for me and Henry."
..."
Maybe Astra can help Audrey
Astra I don’t think you’re supposed to chat in this thread. This is just for me and Henry."
..."
Maybe Astra can help Audrey
Yes, maybe. But if she can help she can go in any thread. I made Henry a mod cuz I'll be off soon. But anyone cna help, as long as they aren't trying to get the wrong answer.
Hi is anyone on? I need help with some math :/
I’m in 8th, but have taken Honors Algebra 2.
Ok, I can help you then. Let me know the problem your stuck on. :)
(i) 2/9 by 4/5
(ii) 3/5 by 12
(iii) 2¹/₃ by 2/5
(iv) 5³/₄ by 2³/₇
(ii) 3/5 by 12
(iii) 2¹/₃ by 2/5
(iv) 5³/₄ by 2³/₇
I believe so. Not sure, I do online school and zoom so we use this website for our math and she tells us what problems to do but she’s really confusing...she just typed this to our school chat in this message app: “here is the extra math. I know we did math this morning over zoom but we always do extra math. I am only typing this for Krystal because she is new to this class.”
If you are multiplying, then here is how to solve the problems:1. Multiply numerator by numerator and denominator by denominator. Then simplify it.
2. Turn 12 into 12/1 and follow the steps for the first problem.
3. Turn 2 into 7/3 by multiplying 2 and 3 and adding 1. Then follow directions for step one.
4. Do the same for both numbers and follow directions on problem one.
(I’m pretty sure this is the right way to solve them, but I may be wrong.)
Ok I did what you said...I can send the page yet though. THERE IS MORE.
2/9 by 4/5
= 2/9 × 4/5
= (2 × 4)/(9 × 5)
= 8/45
= 2/9 × 4/5
= (2 × 4)/(9 × 5)
= 8/45
Alright, give me some time to type it out. I’m on my iPad so it takes a while.
Ok. I’m on a laptop. Not a chrome book, a Apple laptop :>
Simplify the fractions:
(i) 5 × 3/20 × 2/15
(ii) 14/25 × 35/51 × 34/49
(i) 5 × 3/20 × 2/15
(ii) 14/25 × 35/51 × 34/49
1. Turn 5 into 5/1 and multiply it with 3/20. Simplify that answer and multiply it with 2/15. Then simplify it again to get the final answer.
